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# Physics SPH3U

This course develops students' understanding of the basic concepts of physics. Students will study the laws of dynamics and explore different kinds of forces, the quantification and forms of energy (mechanical, sound, light, thermal, and electrical), and the way energy is transformed and transmitted. They will develop scientific-inquiry skills as they verify accepted laws and solve both assigned problems and those emerging from their investigations. Students will also analyze the interrelationships between physics and technology, and consider the impact of technological applications of physics on society and the environment. Prerequisite: Grade 10 Science SNC2D (Academic)

q = mc∆T

# Waves and Sound

## The equation for period of a pendulum (T), where l is length in meters, and g is gravity, in m/s2.

$T = 2\pi \sqrt{\dfrac{l}{g}}$

## The frequency in a standing wave on a string is 800 Hz.

$f \ = \ \dfrac{v}{λ} \ = \ n\cdot \dfrac{v}{2L}$

## The table below shows the relationship between harmonic number and wavelength for closed pipes/tubes/columns.

 Harmonic Amount of Wavelength in Column Length (m) Wavelength (m) 1 $\dfrac{1}{4}$ $L = \dfrac{1}{4}·λ$ $λ = \dfrac{4}{1}·L$ 3 $\dfrac{3}{4}$ $L = \dfrac{3}{4}·λ$ $λ = \dfrac{4}{3}·L$ 5 $\dfrac{5}{4}$ $L = \dfrac{5}{4}·λ$ $λ = \dfrac{4}{5}·L$ 7 $\dfrac{7}{4}$ $L = \dfrac{7}{4}·λ$ $λ = \dfrac{4}{7}·L$

# Electricity and Magnetism

## Match the correct equations with the type of circuits below.

1. RT = R1 + R2 + ...
2. $\dfrac{1}{R_T} = \dfrac{1}{R_1} + \dfrac{1}{R_2} + ...$
3. VT = V1 + V2 + ...
4. VT = V1 = V2 = ...
5. iT = i1 + i2 + ...
6. iT = i1 = i2 = ...

V = i R

# Magnetism: Induction

## A primary circuit in a step up transformer has a 120 V potential difference and 230 turns.

### If the primary current is 10 A, determine the current in the secondary circuit. Solution i = Hint Clear Info Incorrect Attempts: CHECK A Hint Unavailable \begin{align} \frac{V_s}{V_p} & = \frac{N_s}{N_p} = \frac{I_p}{I_s} \\ \\ \frac{V_s}{V_p} & = \frac{I_p}{I_s} \\ \\ \frac{I_s}{I_p} & = \frac{V_p}{V_s} \\ \\ I_s & = \frac{V_p}{V_s} \cdot I_p \\ \\ & = \frac{120\ V}{261\ V} \cdot 10\ A \\ \\ & = 4.6\ A \\ \\ \end{align}

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