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Math

Students are expected to build on their knowledge from the previous year, at a higher level of complexity. The depth of concepts, mathematical procedures and processes will be expanded each year. Elementary school is an important time in your child's academic development. Find out how an individualized approach to learning can build the skills, habits and attitudes your child needs for a solid academic foundation and a lifetime of success. Prerequisite: Math 5

INCORRECT

Number Sense and Numeration

Given the following 3 different examples of ways to solve, use whatever method you prefer, and enter your answer as a fully reduced, mixed fraction.

$4\,\dfrac{1}{4} - 2\,\dfrac{2}{3}$ $\begin{array}{lcl} \underline{\text{Method #1}} & & \underline{\text{Method #2}} & & \underline{\text{Method #3}} \\ = 4 - 2 + \left(\dfrac{1}{4} - \dfrac{2}{3}\right) & & = 4 - 2 + \left(\dfrac{1}{4} - \dfrac{2}{3}\right) & & = 4 + \dfrac{1}{4} - \left(2 + \dfrac{2}{3}\right) \\ = 2 + \left(\dfrac{1}{4} - \dfrac{2}{3}\right) & & = 2 + \left(\dfrac{3}{12} - \dfrac{8}{12}\right) & & = \dfrac{48}{12} + \dfrac{3}{12} - \left(\dfrac{24}{12} + \dfrac{8}{12}\right) \\ = 1 + \left(1 + \dfrac{1}{4} - \dfrac{2}{3}\right) & & = 2 + \left(- \dfrac{5}{12}\right) & & = \dfrac{48}{12} + \dfrac{3}{12} - \dfrac{24}{12} - \dfrac{8}{12} \\ = 1 + \left(\dfrac{12}{12} + \dfrac{3}{12} - \dfrac{8}{12}\right) & & = 2 - \dfrac{5}{12} & & = \dfrac{48 + 3 - 24 - 8}{12} \\ = 1 + \left(\dfrac{12 + 3 - 8}{12}\right) & & = \dfrac{24}{12} - \dfrac{5}{12} & & = \dfrac{19}{12} \\ = 1 + \dfrac{7}{12} & & = \dfrac{24 - 5}{12} & & = 1 + \dfrac{7}{12} \\ = 1\,\dfrac{7}{12} & & = \dfrac{19}{12} & & \\ & & = 1\,\dfrac{7}{12} & & \\ \end{array}$

The rules for multiplying decimals are:

1. Count the total number of decimal places in the numbers (your magic number).
2. Multiply normally, as if without decimals
3. Once you have the final product, put the decimal at the furthest position to the right
4. Move the decimal to the left by the total number of decimal places (your magic number).

Remember, the rules for multiplying decimals are:

1. Count the total number of decimal places in the numbers (your magic number).
2. Multiply normally, as if without decimals
3. Once you have the final product, put the decimal at the furthest position to the right
4. Move the decimal to the left by the total number of decimal places (your magic number).

Solve the questions below using the following example as a guide.

\begin{align} \quad\quad\quad\quad & 536 \div 1.6 \\ & = 1.6 \big) \!\!\! \overline{\ \ 536} \\ & = 1.6 \big) \!\!\! \overline{\ \ 536.0} \\ & = 16 \big) \!\!\! \overline{\ \ 5360} \\ & = \text{...} \\ \end{align} \begin{align} 335 & \quad\quad\quad\quad \\ 16 \big) \!\!\! \overline{\ \ 5360} & \\ \underline{48} \ | \ | & \\ 5 6 \ | & \\ \underline{\ 4 8 \ } | & \\ 8 \, 0 & \\ \underline{\ 8 \, 0} & \\ 0 & \\ \\ \\ \end{align}

Use estimation and mental math to determine the most accurate answer. Some examples of estimation according to current curriculum guidelines:

8 ≈ 10
22 ≈ 20
113 ≈ 100
562 ≈ 1,000
1,200 ≈ 1,000
19,201 ≈ 20,000
132,092 ≈ 100,000

Measurement

Convert the following, given:

 Pair A: 1,000 m 1 km Pair B: 100 cm 1 m Pair C: 10 mm 1 cm
Remember to move the decimal place by 'the number of zeros' in the "Pair"...

The diagram below shows the same size squares, one is in units of meters, the other is in units of centimeters. Given the rectangle, Geometry and Spatial Sense

Look at the differences in the angles in these triangles... Look at the differences in the side lengths in these triangles, indicated by the different number of tick marks. Given the pattern for the sum of the angles in the regular polygons... Patterning and Algebra

Substitute the given numbers in the equation and multiply, like this for example:

\begin{align} a & = 1 \\ b & = 2 \\ c & = 3 \\ \end{align} \begin{align} & 3abc \\ \\ & = 3 × a × b × c \\ \\ & = 3 × 1 × 2 × 3 \\ \\ & = 3 × 1 × 6 \\ \\ & = 3 × 6 \\ \\ & = 18 \\ \\ \end{align}

P = 2L + 2W

Data Management and Probability

Describe how changing the scale of a graph can alter the appearance in favor of the creator of the graph.  Solution Hint Clear Info Incorrect Attempts: CHECK Hint Unavailable Changing the scale of the axis on the left (y-axis) can make the graph appear smaller, or larger.  Percent complete:
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