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Physics SPH3U

This course develops students' understanding of the basic concepts of physics. Students will study the laws of dynamics and explore different kinds of forces, the quantification and forms of energy (mechanical, sound, light, thermal, and electrical), and the way energy is transformed and transmitted. They will develop scientific-inquiry skills as they verify accepted laws and solve both assigned problems and those emerging from their investigations. Students will also analyze the interrelationships between physics and technology, and consider the impact of technological applications of physics on society and the environment. Prerequisite: Grade 10 Science SNC2D (Academic)

Kinematics

A baseball is thrown horizontally off a cliff and takes 4.0 s to reach the ground. It travels a distance of 25 m from the base of the cliff. Energy, Work, and Power

Workequals zero in which of the following situations? Solution Work due to gravity on a hockey puck sliding with constant velocity across a frictionless surface. Work done on an object that experiences no forces. Work due to the normal force of a computer resting on the flat surface of a table. II only III only I and III I, II, and III W = F · d Work equals zero when the distance direction is not parallel to the force direction. Force of gravity is vertical while the distance travelled is horizontal, or the distance in the same direction is zero, so work is zero. Force equals zero, so work equals zero. Distance equals zero, so work equals zero.

Mechanical Energy An elevator weighs 8000 kg when fully loaded and must travel a height of 80 m from the ground to the top floor of a building. The company needs the elevator to make it to the top in 20 seconds. q = mc∆T

Waves and Sound

Given the diagram below, A pendulum begins oscillating at point A. The equation for period of a pendulum (T), where l is length in meters, and g is gravity, in m/s2.

$T = 2\pi \sqrt{\dfrac{l}{g}}$

The frequency in a standing wave on a string is 800 Hz.

$f \ = \ \dfrac{v}{λ} \ = \ n\cdot \dfrac{v}{2L}$

The table below shows the relationship between harmonic number and wavelength for closed pipes/tubes/columns.

 Harmonic Amount of Wavelength in Column Length (m) Wavelength (m) 1 $\dfrac{1}{4}$ $L = \dfrac{1}{4}·λ$ $λ = \dfrac{4}{1}·L$ 3 $\dfrac{3}{4}$ $L = \dfrac{3}{4}·λ$ $λ = \dfrac{4}{3}·L$ 5 $\dfrac{5}{4}$ $L = \dfrac{5}{4}·λ$ $λ = \dfrac{4}{5}·L$ 7 $\dfrac{7}{4}$ $L = \dfrac{7}{4}·λ$ $λ = \dfrac{4}{7}·L$

Electricity and Magnetism

Match the correct equations with the type of circuits below. 1. RT = R1 + R2 + ...
2. $\dfrac{1}{R_T} = \dfrac{1}{R_1} + \dfrac{1}{R_2} + ...$
3. VT = V1 + V2 + ...
4. VT = V1 = V2 = ...
5. iT = i1 + i2 + ...
6. iT = i1 = i2 = ...

V = i R

Magnetism: Induction

A primary circuit in a step up transformer has a 120 V potential difference and 230 turns.

If the primary current is 10 A, determine the current in the secondary circuit. Solution i = Hint Clear Info Incorrect Attempts: CHECK A Hint Unavailable \begin{align} \frac{V_s}{V_p} & = \frac{N_s}{N_p} = \frac{I_p}{I_s} \\ \\ \frac{V_s}{V_p} & = \frac{I_p}{I_s} \\ \\ \frac{I_s}{I_p} & = \frac{V_p}{V_s} \\ \\ I_s & = \frac{V_p}{V_s} \cdot I_p \\ \\ & = \frac{120\ V}{261\ V} \cdot 10\ A \\ \\ & = 4.6\ A \\ \\ \end{align} Percent complete:
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